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Sinusoidal steady state response

Consider a causal system having a transfer function :

displaymath626

subjected to the sinusoidal input sequence :

displaymath627

Theorem on steady state response

The system steady-state output response is :

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So the output is a sinusoid at the same digital frequency. The amplitude gain of the system is tex2html_wrap_inline670 and the phase shift through the system is tex2html_wrap_inline672 .

Discussion

We need to first calculate the z-transform of the response :

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displaymath631

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From our table of transforms :

displaymath634

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Poles of Y(z)
From H(z) the poles are tex2html_wrap_inline678 say
From X(z) the poles are tex2html_wrap_inline682

Note that the residues of the X(z) poles are a complex conjugate pair. When H(z) and Y(z) are multiplied out the resulting Y(z) (represented as a sum of partial fractions) will have the form :

displaymath636

where tex2html_wrap_inline692 and tex2html_wrap_inline694 are a complex conjugate pair.

Take the inverse z-transform (causal sequence) :

displaymath637

The terms tex2html_wrap_inline696 are transients, decaying to zero as tex2html_wrap_inline698 .

displaymath638

Evaluate tex2html_wrap_inline692 and tex2html_wrap_inline694 in the usual way for partial fractions - divide by z , multiply by tex2html_wrap_inline706 and evaluate the result at tex2html_wrap_inline708 :

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Put tex2html_wrap_inline708 and get :

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Similarly we find :

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displaymath645

displaymath646

displaymath647

Conventionally we write : tex2html_wrap_inline712



Keith Jones
Tue Oct 27 11:32:15 EST 1998