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Series RL circuit

A series resistance R and self-inductance L is driven by an input voltage tex2html_wrap_inline410 . The output voltage tex2html_wrap_inline412 across the inductor is measured by a very high impedance device which consequently draws negligible current from the circuit. Use the complex number method to calculate the current I in the circuit and the voltage tex2html_wrap_inline412 across the inductor. So think of the input voltage as the real part of tex2html_wrap_inline418 .

  1. Show that the complex number representation of the current is:

    displaymath382

    displaymath383

    SOLUTION:

    We use tex2html_wrap_inline420 to represent the complex number version of the real V.

    displaymath384

    displaymath385

    displaymath386

    displaymath383

  2. The complex number representation of the output voltage tex2html_wrap_inline424 will be the current times the complex impedance of the inductor. Hence show that:

    displaymath388

    SOLUTION:

    Using tex2html_wrap_inline426 :

    displaymath389

  3. Show that the actual voltage across the inductor is:

    displaymath390

    (Remember tex2html_wrap_inline428 .)

    SOLUTION:

    The actual voltage is :

    displaymath391

    displaymath392

    Hence the result.

  4. What are the filter properties of this circuit? i.e. is it highpass, lowpass etc.

    SOLUTION:

    displaymath393

    Hence it is a highpass filter.



Keith Jones
Fri Mar 3 10:00:43 EST 2000