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Resonant absorption in a dielectric

Calculate wave propagation properties of the medium in the previous question but for a 10GHz wave. i.e. the wave frequency is equal to the resonant frequency of the molecules.

Show that the medium is very strongly absorbing. Can you understand this result physically?

SOLUTION:

In this case:

displaymath570

since tex2html_wrap_inline592 .

From previous working we have:

displaymath571

displaymath572

displaymath573

displaymath574

The wave propagation factor is:

displaymath575

The phase velocity is then:

displaymath576

The wave field varies like:

displaymath577

The absorption coefficient tex2html_wrap_inline594 .
So the attenuation length (the distance over which the amplitude falls by a factor tex2html_wrap_inline596 ) is:

displaymath578

and:

displaymath579

not very big!!

Here we are not really describing a propagating wave. It is so massively attenuated.

So if energy is lost from the incident wave where does it go? There is no mechanism here for absorption in to internal degrees of freedom of the molecules. There must be an equilibrium set up between the rate of absorption of radiation by the electrons and re-radiation.

The predominant importance of the tex2html_wrap_inline558 factor in the expression for tex2html_wrap_inline600 shows the radiation reaction force plays a dominant role in the motion of the electrons.
The radiation reaction force depends on tex2html_wrap_inline602 whereas normally, radiation depends on the acceleration tex2html_wrap_inline604 . So the re-radiated wave must cancel the incident wave in the direction of its propagation. The re-radiated energy must go off in other directions.



Keith Jones
Thu May 11 11:04:49 EST 2000